Physics Of Soccer Research Paper

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Every four years there is one sport that unites the world in pursuit of the most coveted trophy in all of sports history. Every year there are countless leagues that have seasons were the most talented players fight for the league title. Every day, teenagers, students and children play on green fields to get hours of exercise. If it is not evident yet, the sport previously mentioned is soccer. To this day, soccer is one of the most liked sports in the world. Behind this sport, is an ever-growing fan base. Many people merely watch the sport but others, due to their love of the game, play this great sport. Behind all this excitement and enjoyment that is soccer, there exists another intriguing side of soccer. Behind every goal, behind every shot,…show more content…
Soccer is a game where two opposing teams, composed of eleven players on each team, try to score on the opposing teams goal. Each team is made up of one goalie, a player that protects the goal (the only player that can touch the ball with their hands), a number of defenders, a number of midfielders, and one or two forwards. According to the Fédération Internationale de Football Association or FIFA, the official size of the soccer ball must be 68 centimeters (27 inches) to 70 centimeters (28 inches) in circumference. The conversion from centimeters to feet is seen below. (One centimeter is equivalent to 0.394 inches, so to get this conversion, first it is necessary to multiply the number of centimeters by 0.394 and then divide the product of this…show more content…
Since the vertical vector is on the opposite side of the 30°, the formula for sine will be used. sin⁡〖30°= (the velocity of the vertical vector)/(61.6 ft⁄sec)〗 Multiply both sides by 61.6 (61.6)sin⁡〖30°〗=the velocity of the vertical vector Multiply velocity of vertical vector= 30.8 ft⁄sec The significance of the velocity of the vertical vector being 30.8 ft/sec is that as the ball is moving at 61.6 ft/sec it is moving upwards at 30.8 ft/sec. Though this information is useful, it is only part of what is needed to determine the distance that the soccer ball will go. To be able to proceed, it is key that the amount of time that the ball spends in the air is found. amount of time spent in the air(going up and down)= acceleration through gravity × ∆T The acceleration for gravity when the object is going down is -32.2 ft⁄sec -61.6ft⁄(sec=) -32.2 ft⁄(〖sec〗^2 × ∆T) Divide each side by 32.2 1.91 seconds of air time The next step in finding the distance that the ball will travel is to find the horizontal vector. The horizontal vector is adjacent to the 30°, the formula for cosine will be

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